117 lines
3.2 KiB
Java
117 lines
3.2 KiB
Java
package lingtao.net.util;
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import java.util.ArrayList;
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import java.util.List;
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import lingtao.net.bean.Product;
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/**
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* 哑金/哑银不干胶价格
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*/
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public class YaJinStickersPrice {
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int countArr[] = { 500, 1000, 2000, 3000, 4000, 5000, 10000 };
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// 根据尺寸计算价格
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public List<Product> accountPriceBySize(Double width, Double length, int count, int[] priceArr1, int[] priceArr2,
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int[] priceArr3) {
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List<Product> list = new ArrayList<Product>();
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if ((length <= 6 && width <= 5) || (length <= 5 && width <= 6) || (length <= 10 && width <= 3)
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|| (length <= 3 && width <= 10)) {
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list = getPrice(count, priceArr1);
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} else if ((length <= 8 && width <= 8) || (length <= 10 && width <= 6) || (length <= 6 && width <= 10)) {
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list = getPrice(count, priceArr2);
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} else if ((length <= 11 && width <= 11) || (length <= 12 && width <= 8) || (length <= 8 && width <= 12)
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|| (length <= 20) && (width <= 4) || (width <= 20) && (length <= 4)) {
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list = getPrice(count, priceArr3);
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} else {
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return null;
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}
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return list;
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}
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// 6*5cm以下及10*3cm以下
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// 6*5cm-8*8cm;10-3cm-10*6cm以内
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// 8*8cm-11*11cm;10*6-12*8CM;20*4以内
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private List<Product> getPrice(int count, int[] priceArr) {
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Product pro = new Product();
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List<Product> list = new ArrayList<Product>();
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// 数量大于10000
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if (count > countArr[countArr.length - 1]) {
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pro.setCount(count);
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// 10000个的单价*数量
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pro.setPrice(Math.ceil(count * priceArr[countArr.length - 1] / countArr[countArr.length - 1]));
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list.add(pro);
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}
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for (int i = 0; i < countArr.length; i++) {
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if (countArr[i] < count) {
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continue;
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}
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pro = new Product();
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pro.setCount(countArr[i]);
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pro.setPrice(Math.ceil(priceArr[i]));
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list.add(pro);
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}
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return list;
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}
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// 哑金不干胶不带凹凸
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public List<Product> getPriceNoAoTu(Double length, Double width, int count) {
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double l = 404;
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double w = 289;
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double price = 0.0;
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List<Product> list = new ArrayList<Product>();
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Product pro = new Product();
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// 换成毫米每边+2
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length = length * 10 + 4;
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width = width * 10 + 4;
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if ((length > l || width > w) && (length > w || width > l))
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return null;
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// 一张A4纸 大的400*285 能做多少个此类尺寸的不干胶
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double max = Math.max(Math.floor(l / length) * Math.floor(w / width),
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Math.floor(l / width) * Math.floor(w / length));
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// 报的数量需要多少张大纸
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int num = (int) Math.ceil(count / max);
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if (max <= 20) {
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price = 65;
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} else if (max <= 50) {
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price = 75;
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} else if (max <= 100) {
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price = 85;
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} else if (max <= 200) {
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price = 100;
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} else if (max <= 300) {
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price = 110;
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} else {
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price = 150;
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}
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if (max <= 200) {
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/*price = price + (num - 1) * 12;
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// if (num > 10) {
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// price = price + (num - 1) * 10;
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// } else {
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// price = price + (num - 1) * 20;
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// }*/
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if(num < 50) {
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price = price + (num - 1 ) * 12;
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}else if(num <= 100) {
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price = price + (num - 1 ) * 10;
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}else {
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price = price + (num - 1 ) * 6;
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}
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} else {
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if (num > 10) {
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price = price + (num - 1) * 10;
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} else {
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price = price + (num - 1) * 30;
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}
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}
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pro.setCount(count);
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pro.setPrice(price);
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list.add(pro);
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return list;
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}
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}
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